Electronic Components Example

An electronic component was redesigned and then tested to failure at three different temperatures. Six units were tested at each temperature level. At the 406K stress level, however, a unit was removed from the test due to a test equipment failure which led to a failure of the component. A warranty time of one year is to be given, with an expected return of 10% of the population. The following table shows the times-to-failure and test temperatures.



The operating temperature is 356K. Using the Arrhenius-Weibull model, determine the following:

1) Should the first failure at 406K be included in the analysis?

2) Determine the warranty time for a 90% reliability.

3) Determine the 90% lower confidence limit on the warranty time.

4) Is the warranty requirement met? If not, what steps should be taken?

5) Repeat the analysis with the unrelated failure included. Is there any difference?

6) If the unrelated failure occurred at 500 hr, should it be included in the analysis?

Solution

1) Since the failure occurred at the very beginning of the test and for an unrelated reason, it can be omitted from the analysis. If it is included it should be treated as a suspension and not as a failure.

2) Disregard the first failure at 406K and analyze the data using the ALTA standard folio. The estimated parameters are:


 * $$\begin{align}

\beta =\ & 2.965820 \\

B=\ & 10679.567542 \\

C=\ & 2.396615\cdot {{10}^{-9}}

\end{align}$$

The following plot shows the use level probability plot of the analysis. The warranty time for a reliability of 90% (or an unreliability of 10%) can be estimated from this plot, as shown next.



This estimate can also be obtained from the Arrhenius plot (Life vs. Stress plot). The 10th percentile (time for a reliability of 90%) is plotted versus stress. This type of plot is useful because it allows you to determine a time for a given reliability for different stress levels.



A more accurate way to determine the warranty time would be to use ALTA's Quick Calculation Pad (QCP). In the QCP, select to calculate Reliable Life and enter 356 for the stress and 0.9 for the required reliability. The reliable life is estimated to be 11,977.792719 hr, as shown next:



3) From the use level probability plot, the warranty time for a 90% reliability was estimated to be approximately 12,000 hr. This is above the 1 year (8,760 hr) requirement. However, this is an estimate at the 50% confidence level. In other words, 50% of the time life will be greater than 12,000 hr and 50% of the time life will be less. A known confidence level is therefore crucial before any decisions are made.

Plot the confidence bounds on both probability and Arrhenius plots. The following use level probability plot, shows the 90% lower confidence level (LCL). Note that in ALTA, percentile bounds are Type 1 confidence bounds.



From the plot, we obtain an estimate of 4,437 hr warranty time at a 90% lower confidence level. This means that 90% of the time, life will be greater than this value. In other words, a life of 4,437 hr is a bounding value for the warranty. The Arrhenius plot with the 90% lower confidence level is shown next.



To use the QCP to calculate the lower confidence bound, click the Bounds button and select Lower-One Sided from the drop-down list. The result shows a lower bound of 4,436.506367 hr.



4) The warranty time for this component is estimated to be 4,436.5 hr at a 90% lower confidence bound. This is much less than the 1 year warranty time required (almost 6 months). Thus the desired warranty is not met. In this case, the following four options are available:


 * a) Redesign.


 * b) Reduce the confidence level.


 * c) Change the warranty policy.


 * d) Test additional units at stress levels closer to the use level.

5) Including the unrelated failure of 0.3 hr at 406 K (by treating it as a suspension) in the analysis obtains the following results:
 * $$\begin{align}

\beta =\ & 2.965804 \\

B=\ & 10679.566625 \\

C=\ & 2.396619\cdot {{10}^{-9}}

\end{align}$$

These results are essentially identical to the results obtained when the unrelated failure was excluded. A small difference can be seen only if more significant digits are considered. The warranty time with the 90% lower 1-sided confidence bound is estimated to be:


 * $$\begin{align}

T=\ & 11977.729145\text{ hr} \\

{{T}_{L}}=\ & 4436.462084\text{ hr}

\end{align}$$

Again, the difference is negligible. This is due to the very early time at which this unrelated failure occurred.

6) Repeat the analysis treating the unrelated failure at 500 hr as a suspension. The results are:


 * $$\begin{align}

\beta =\ & 3.022714 \\

B=\ & 10959.523204 \\

C=\ & 1.23808\cdot {{10}^{-9}}

\end{align}$$

In this case, the results are very different. The warranty time with the 90% lower 1-sided confidence bound is estimated to be:


 * $$\begin{align}

T=\ & 13780.208409\text{ hr} \\ {{T}_{L}}=\ & 5303.672050\text{ hr} \end{align}$$

As you can see, it would be a mistake to neglect the unrelated failure in this case. By neglecting this failure, we would actually underestimate the warranty time. The important observation in this example is that every piece of life information is crucial. In other words, unrelated failures also provide information about the life of the product. An unrelated failure occurring at 500 hr indicates that the product has survived for that period of time under the particular stress level; thus, neglecting it would be a mistake. On the other hand, it would also be a mistake to treat this data point as a failure, since the failure was caused by the faulty test equipment.