Template:Alta exponential mean - Revision history

Richard House: Redirected page to Distributions Used in Accelerated Testing

2012-08-16T01:29:05Z

Redirected page to Distributions Used in Accelerated Testing

← Older revision		Revision as of 01:29, 16 August 2012
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	~~==== The Mean or MTTF ====~~		#REDIRECT [[Distributions_Used_in_Accelerated_Testing]]

	~~The mean, <math>\overline{T}</math>, or mean time to failure (MTTF) of the 1-parameter exponential distribution is given by:~~

	~~<br>~~

	~~::<math>\begin{align}~~
	~~\overline{T}& = \int_{0}^{\infty }t\cdot f(t)dt=\int_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt = \frac{1}{\lambda }~~
	~~\end{align}</math>~~

	~~<br>~~

Chris Kahn at 22:30, 6 March 2012

2012-03-06T22:30:10Z

← Older revision		Revision as of 22:30, 6 March 2012
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	====The Mean or MTTF====		==== The Mean or MTTF ====
	The mean, <math>\overline{T},</math> or ~~Mean Time To Failure~~ (MTTF) of the 1-parameter exponential distribution is given by:
			The mean, <math>\overline{T}</math>, or mean time to failure (MTTF) of the 1-parameter exponential distribution is given by:

			<br>

	~~<br>~~
	::<math>\begin{align}		::<math>\begin{align}
	\overline{T}& = \int_{0}^{\infty }t\cdot f(t)dt=\int_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt = \frac{1}{\lambda }		\overline{T}& = \int_{0}^{\infty }t\cdot f(t)dt=\int_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt = \frac{1}{\lambda }

Athanasios Gerokostopoulos: /* The Mean or MTTF */

2012-02-27T22:37:44Z

The Mean or MTTF

← Older revision		Revision as of 22:37, 27 February 2012
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	====The Mean or MTTF====		====The Mean or MTTF====
	The mean, <math>\overline{T},</math> or Mean Time To Failure (MTTF) of the 1-parameter exponential distribution is given by:		The mean, <math>\overline{T},</math> or Mean Time To Failure (MTTF) of the 1-parameter exponential distribution is given by:

	<br>		<br>
	::<math>\begin{align}		::<math>\begin{align}
	\overline{T}& = \int_{0}^{\infty }t\cdot f(t)dt=\int_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt \\		\overline{T}& = \int_{0}^{\infty }t\cdot f(t)dt=\int_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt = \frac{1}{\lambda }
	& = \frac{1}{\lambda }
	\end{align}</math>		\end{align}</math>

			<br>

Athanasios Gerokostopoulos at 23:26, 6 February 2012

2012-02-06T23:26:54Z

← Older revision		Revision as of 23:26, 6 February 2012
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	<br>		<br>
	::<math>\begin{align}		::<math>\begin{align}
	\overline{T}& = \~~mathop{}_~~{0}^{\infty }t\cdot f(t)dt=\~~mathop{}_~~{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt \\		\overline{T}& = \int_{0}^{\infty }t\cdot f(t)dt=\int_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt \\
	& = \frac{1}{\lambda }		& = \frac{1}{\lambda }
	\end{align}</math>		\end{align}</math>

Athanasios Gerokostopoulos at 23:21, 6 February 2012

2012-02-06T23:21:44Z

← Older revision		Revision as of 23:21, 6 February 2012
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	<br>		<br>
	::<math>\begin{align}		::<math>\begin{align}
	& \overline{T}= & \mathop{}_{0}^{\infty }t\cdot f(t)dt=\mathop{}_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt \\		\overline{T}& = \mathop{}_{0}^{\infty }t\cdot f(t)dt=\mathop{}_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt \\
	& = & \frac{1}{\lambda }		& = \frac{1}{\lambda }
	\end{align}</math>		\end{align}</math>

Nicolette Young: Created page with '====The Mean or MTTF==== The mean, $\overline{T},$ or Mean Time To Failure (MTTF) of the 1-parameter exponential distribution is given by:
:: $\begin{align}…'$

2012-01-12T18:08:51Z

Created page with '====The Mean or MTTF==== The mean, <math>\overline{T},</math> or Mean Time To Failure (MTTF) of the 1-parameter exponential distribution is given by: <br> ::<math>\begin{align}…'

New page

====The Mean or MTTF====
The mean, <math>\overline{T},</math> or Mean Time To Failure (MTTF) of the 1-parameter exponential distribution is given by:
<br>
::<math>\begin{align}
& \overline{T}= & \mathop{}_{0}^{\infty }t\cdot f(t)dt=\mathop{}_{0}^{\infty }t\cdot \lambda \cdot {{e}^{-\lambda t}}dt \\
& = & \frac{1}{\lambda }
\end{align}</math>