User:Kate Racaza/test page: Difference between revisions

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==TEST PAGE==
==TEST PAGE==


The first possibility is the probability of a successful trial, <math>(1-p)</math>, where <math>p</math> is the probability of failure in trial <math>n-1</math>, while being in the unreliable state, <math>P_{n-1}(0)</math>, before the <math>n-1</math> trial, or:  
The first possibility<ref>source</ref> is the probability of a successful trial, <math>(1-p)</math>, where <math>p</math> is the probability of failure in trial <math>n-1</math>, while being in the unreliable state, <math>P_{n-1}(0)</math>, before the <math>n-1</math> trial, or:  


::<math>(1-p)P_{n-1}(0)</math>
::<math>(1-p)P_{n-1}(0)</math>


::<math>ax^2 + bx + c = 0</math>
::<math>ax^2 + bx + c = 0</math>
==References==
<references />





Revision as of 15:15, 31 January 2013

TEST PAGE

The first possibility<ref>source</ref> is the probability of a successful trial, [math]\displaystyle{ (1-p) }[/math], where [math]\displaystyle{ p }[/math] is the probability of failure in trial [math]\displaystyle{ n-1 }[/math], while being in the unreliable state, [math]\displaystyle{ P_{n-1}(0) }[/math], before the [math]\displaystyle{ n-1 }[/math] trial, or:

[math]\displaystyle{ (1-p)P_{n-1}(0) }[/math]
[math]\displaystyle{ ax^2 + bx + c = 0 }[/math]


References

<references />


Examples of expressions that are always rendered as PNG images

[math]\displaystyle{ x={-b\pm\sqrt{b^2-4ac} \over 2a} }[/math]

[math]\displaystyle{ 2 = \left( \frac{\left(3-x\right) \times 2}{3-x} \right) }[/math]


Use \textstyle markup to make it smaller: [math]\displaystyle{ \textstyle 2 = \left( \frac{\left(3-x\right) \times 2}{3-x} \right) }[/math]



Regular size formula:

The formula [math]\displaystyle{ \sum_{n=1}^\infty 1/n^2 = \pi^2/6 }[/math] is used for...

\textstyle markup:

The formula [math]\displaystyle{ \textstyle\sum_{n=1}^\infty 1/n^2 = \pi^2/6 }[/math] is used for...

Mix of HTML and TeX markup:

TPH = [math]\displaystyle{ \tau }[/math](DTO4 – DTR1)


All TeX markup:

[math]\displaystyle{ TPH = \tau(DTO_{4}-DTR_{1}) }[/math]