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  • | 1||-1||1||1||1||-1||-1||-1||1||-1||1||1||220 | 2||-1||1||1||-1||1||1||1||-1||-1||-1||1||207
    2 KB (222 words) - 21:09, 18 September 2023
  • Table 6.2 on page 283 in the book ''Reliability Engineering Handbook Vol 1'' by Dr. Kececioglu, Prentice-Hall, 1991. |1 ||F |||16
    969 bytes (120 words) - 16:20, 28 September 2015
  • | 1||1||1||1||48||49||56||63 | 2||1||-1||-1||50||52||55||63
    1 KB (194 words) - 21:09, 18 September 2023
  • :{| style="text-align:center;" cellpadding="2" border="1" align="center" |1|| -1|| -1|| -1|| -1|| -1
    4 KB (636 words) - 21:07, 18 September 2023
  • {{APIComment|'Add suspensions at times 1, 2 and 3 to the data set.}} {{APIPrefix|Call}} WDS.AddSuspension(1, 1)
    1,021 bytes (108 words) - 22:17, 30 March 2016
  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac | 1||S||9
    1 KB (215 words) - 06:18, 16 August 2012
  • ==Grouped Data Example 1==
    369 bytes (45 words) - 20:35, 18 September 2023
  • Table 6.3 on page 292 in the book ''Reliability Engineering Handbook Vol 1'' by Dr. Kececioglu, Prentice-Hall, 1991. | 1||F||46
    1,001 bytes (138 words) - 16:13, 28 September 2015
  • ::<math>\theta = \frac{2TTT}{x^{2}_{(1-\alpha; 2)}}\,\!</math> ...\!</math> is also the confidence level. The equation above gives the lower 1-sided confidence bound for <math>\theta \,\!</math>.
    993 bytes (135 words) - 16:17, 28 September 2015
  • {{APIPrefix|Call}} WDS.AddFailureInterval(1, 5, 1) {{APIPrefix|Call}} WDS.AddFailureInterval(6, 10, 1)
    1 KB (118 words) - 17:59, 16 January 2018
  • {{APIPrefix|Call}} WDS.AddSuspensionInterval(1, 5, 1) {{APIPrefix|Call}} WDS.AddSuspensionInterval(6, 10, 1)
    1 KB (121 words) - 22:18, 30 March 2016
  • {{APIPrefix|Call}} ADS.AddFailure_2(245, 1, 353) {{APIPrefix|Call}} ADS.AddFailure_2(110, 1, 373)
    2 KB (189 words) - 15:30, 7 September 2016
  • ...{{e}^{-\left( A-\tfrac{B}{V} \right)}}\cdot \Gamma \left( \frac{1}{\beta }+1 \right)\,\!</math> ...frac{1454.08635742}{323} \right)}}\cdot \Gamma \left( \frac{1}{4.29186497}+1 \right) =16,610\text{ }hr
    1 KB (158 words) - 19:02, 18 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac | align="center" | 1 ||align="center" | 2,403||align="center" | Failure
    3 KB (350 words) - 02:45, 16 August 2012
  • ...ce bounds are calculated by finding values for <span class="texhtml">θ<sub>1</sub></span> and <span class="texhtml">θ<sub>2</sub></span> that satisfy: ...eta _{2})}{L(\hat{\theta }_{1}, \hat{\theta }_{2})}\right) =\chi _{\alpha ;1}^{2} </math>
    2 KB (358 words) - 18:21, 28 February 2012
  • | High (+1)||200||10||25 | Low (-1)||150||5||15
    2 KB (273 words) - 21:08, 18 September 2023
  • This example validates the calculations for a 1-parameter Weibull MLE solution with right censored data in Weibull++ standa | 1||F||230
    2 KB (255 words) - 17:51, 31 January 2017
  • ...PIComment|'Get a list of all causes associated with failure #1 in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (136 words) - 18:31, 9 June 2016
  • | 4||0.01||F||1 | 99||0.01||S||1
    984 bytes (131 words) - 16:21, 28 September 2015
  • This example assumes that a system hierarchy item with ID#1 exists in the first available project of a repository. {{APIComment|'Get system hierarchy item #1 from project #1.}}
    2 KB (187 words) - 18:43, 9 June 2016
  • This example assumes that a failure with ID#1 exists in a repository. {{APIComment|'Get failure #1 from project #1.}}
    2 KB (187 words) - 18:45, 9 June 2016
  • This example assumes that a cause with ID #1 exists in the first available project of a repository. {{APIComment|'Get cause #1 from project #1.}}
    2 KB (213 words) - 18:48, 9 June 2016
  • This example assumes that an Xfmea control with ID #1 exists in the first available project in a repository. {{APIComment|'Get control #1 from project #1.}}
    2 KB (213 words) - 16:55, 9 June 2016
  • This example assumes that an effect with ID#1 exists in a repository. {{APIComment|'Get effect #1 from project #1.}}
    2 KB (187 words) - 18:44, 9 June 2016
  • ...idates the calculations for the MLE solution and Fisher Matrix bound for a 1-parameter exponential distribution with right censored and complete failure | 1||F||16
    1 KB (158 words) - 16:17, 28 September 2015
  • This example assumes that a profile with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get profile #1 from project #1.}}
    2 KB (194 words) - 22:17, 22 March 2017
  • This example assumes that an action with ID #1 exists in the first available project of a repository. {{APIComment|'Get action #1 from project #1.}}
    2 KB (213 words) - 15:40, 9 June 2016
  • This example assumes that a URD with ID #1 exists in the first available project of a repository. {{APIComment|'Get URD #1 from project #1.}}
    2 KB (213 words) - 17:45, 9 June 2016
  • This example assumes that a crew with ID #1 exists in the first available project of a repository. {{APIComment|'Get crew #1 from project #1.}}
    2 KB (213 words) - 17:01, 9 June 2016
  • This example assumes that a profile with ID #1 exists in the first available project of a repository. {{APIComment|'Get profile #1 from project #1.}}
    2 KB (213 words) - 23:14, 22 March 2017
  • {{APIPrefix|Call}} wds.AddFailure(100, 1) {{APIPrefix|Call}} wds.AddFailure(120, 1)
    2 KB (246 words) - 23:41, 6 September 2016
  • {| | border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac | 6316||1/1/2010
    4 KB (456 words) - 18:54, 18 September 2023
  • This example assumes that a variable with ID #1 exists in the first available project of a repository. {{APIComment|'Get variable #1 from project #1.}}
    2 KB (213 words) - 17:42, 9 June 2016
  • ...dow, enter the values and select the options shown below for subpopulation 1. [[Image:Mixed Weibull Example 1 Simulation Sub1.png|center|450px| ]]
    2 KB (230 words) - 21:39, 18 September 2023
  • This example assumes that an effect with ID #1 exists in the first available project of a repository. {{APIComment|'Get effect #1 from project #1.}}
    2 KB (213 words) - 18:49, 9 June 2016
  • This example assumes that a scheduled task with ID #1 exists in the first available of a repository. {{APIComment|'Get scheduled task #1 from project #1.}}
    2 KB (215 words) - 17:38, 9 June 2016
  • ...t|'Get a list of all failures associated with FMEA function #1 in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (140 words) - 18:36, 9 June 2016
  • {{APIPrefix|Call}} wds.AddFailure(100, 1) {{APIPrefix|Call}} wds.AddFailure(120, 1)
    2 KB (246 words) - 23:41, 6 September 2016
  • This example assumes that a corrective task with ID #1 exists in the first available project of a repository. {{APIComment|'Get corrective task #1 from project #1.}}
    2 KB (217 words) - 17:37, 9 June 2016
  • This example assumes that an FMEA function with ID#1 exists in a repository. {{APIComment|'Get FMEA function #1 from project #1.}}
    2 KB (194 words) - 18:49, 22 August 2016
  • This example assumes that a failure with ID #1 exists in the first available project of a repository. {{APIComment|'Get function #1 from project #1.}}
    2 KB (213 words) - 18:50, 9 June 2016
  • Table 3.1 on page 78 in the book ''Reliability & Life Testing Handbook Vol 2'' by Dr. |1 ||F |||5100
    2 KB (264 words) - 16:20, 28 September 2015
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |3|| 25|| BC|| 1
    3 KB (373 words) - 20:52, 18 September 2023
  • ...IComment|'Get a list of all effects associated with failure #1 in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (148 words) - 20:40, 18 August 2016
  • This example assumes that a function with ID #1 exists in the first available project of a repository. {{APIComment|'Get FMEA function #1 from project #1.}}
    2 KB (217 words) - 18:57, 22 August 2016
  • This example assumes that a spare part pool with ID #1 exists in the first available project of a repository. {{APIComment|'Get spare part pool #1 from project #1.}}
    2 KB (221 words) - 17:29, 9 June 2016
  • ...ther words, the reliability is either 1 or <math>R \,\!</math> , <math>0<R<1 \,\!</math> . ...the glass is in the unreliable state just before the first trial, <math>P_{1}(0) \,\!</math>.
    5 KB (791 words) - 17:04, 16 December 2015
  • {{APIPrefix|Call}} WDS.AddFailure(10, 1) {{APIPrefix|Call}} WDS.AddFailure(20, 1)
    1,009 bytes (112 words) - 17:59, 16 January 2018
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| F|| 0||
    1 KB (120 words) - 21:20, 18 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1 ||2 ||placebo ||
    3 KB (392 words) - 21:45, 18 September 2023
  • | 30||S||5000||283.15||1 | 1||F||1298||313.15||2
    4 KB (460 words) - 18:20, 28 September 2015
  • {{APIComment|'Connect to project#1 in the repository.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (123 words) - 23:28, 6 September 2016
  • This example validates the calculations for a 1-parameter Weibull with zero failure data in Weibull++ standard folios. ...alculating the <math>\eta \,\!</math> at a given confidence level of <math>1 - \alpha\,\!</math> is on page 195.
    1 KB (169 words) - 16:14, 28 September 2015
  • {{APIPrefix|Call}} WDS.AddFailure(1, 1) {{APIPrefix|Call}} WDS.AddFailure(2, 1)
    2 KB (192 words) - 17:50, 24 June 2016
  • This example assumes that a cause with ID#1 exists in a repository. {{APIComment|'Get cause ID#1 from the first project in the repository.}}
    2 KB (200 words) - 18:44, 9 June 2016
  • \text{1} & \text{5, 10 , 15, 17+} \\ ID & Months ({{t}_{i}}) & State & {{r}_{i}} & 1/{{r}_{i}} & {{M}^{*}}({{t}_{i}}) \\
    7 KB (741 words) - 18:53, 18 September 2023
  • {{APIPrefix|Call}} WDS.AddFailure(16, 1) {{APIPrefix|Call}} WDS.AddFailure(34, 1)
    1 KB (164 words) - 15:28, 7 September 2016
  • !1 |3||0||3||3||4||2||1||5||4||2||3||3||45||2123
    3 KB (270 words) - 16:24, 28 September 2015
  • ...year operating period, with 80% confidence level. Assume that <math>\beta =1\,\!</math>, the number of systems for the test is <math>m=6\,\!</math> and :<math>{{\lambda }_{c}}=\frac{1}{MTB{{F}_{c}}}=2\text{ }failures/\ \ year\,\!</math>
    3 KB (384 words) - 20:55, 18 September 2023
  • {{APIComment|'Connect to project#1 in the repository.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (124 words) - 23:29, 6 September 2016
  • {{APIComment|'Get action #1 from project #1.}} MyRepository.Project.SetCurrentProject(1)
    1 KB (130 words) - 23:53, 13 March 2019
  • {{APIPrefix|Call}} WDS.AddFailure(1, 1) {{APIPrefix|Call}} WDS.AddFailure(2, 1)
    2 KB (212 words) - 00:56, 7 September 2016
  • This example assumes that an Xfmea control with ID#1 exists in a repository. {{APIComment|'Get control #1 from project #1.}}
    2 KB (233 words) - 18:52, 9 June 2016
  • ::<math> \overline{T}=\gamma +\eta \cdot \Gamma \left( {\frac{1}{\beta }}+1\right) \,\!</math> ::<math> \Gamma \left( {\frac{1}{\beta }}+1\right) \,\!</math>
    4 KB (634 words) - 21:40, 18 September 2023
  • This example assumes that a profile with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get profile #1 from project #1.}}
    2 KB (238 words) - 23:14, 22 March 2017
  • This example assumes that an action with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get action #1 from project #1.}}
    2 KB (237 words) - 18:53, 9 June 2016
  • | 1||F||230 | 1||F||334
    1 KB (195 words) - 16:15, 28 September 2015
  • {{APIPrefix|Call}} WDS.AddFailure(16, 1) {{APIPrefix|Call}} WDS.AddFailure(34, 1)
    1 KB (168 words) - 15:34, 7 September 2016
  • ...of all FMEA functions associated with system hierarchy item #1 in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (163 words) - 18:38, 9 June 2016
  • {{APIPrefix|Call}} ADS.AddFailure_2(100, 1, 190) {{APIPrefix|Call}} ADS.AddFailure_2(120, 1, 190)
    1 KB (137 words) - 23:34, 5 May 2016
  • ...en creating the model for the second segment (i.e., data after <math>{{T}_{1}}\,\!</math> ). The models presented next can be applied to the reliability ===Model for First Segment (Data up to <i>T<sub>1</sub></i>)===
    5 KB (750 words) - 20:37, 18 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 53
    2 KB (225 words) - 21:22, 18 September 2023
  • {{APIComment|'Add the new failure to FMEA function #1 located in project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (231 words) - 18:53, 22 August 2016
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 9|| 6|| 0.667|| 0.7002
    4 KB (477 words) - 21:30, 18 September 2023
  • This example assumes that a URD with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get URD #1 from project #1.}}
    2 KB (242 words) - 18:55, 9 June 2016
  • This example assumes that a crew with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get crew #1 from project #1.}}
    2 KB (242 words) - 18:52, 9 June 2016
  • The example assumes that a variable with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get variable #1 from project #1.}}
    2 KB (242 words) - 18:55, 9 June 2016
  • {{APIPrefix|Call}} ADS.AddFailure_2(252, 1, sp) {{APIPrefix|Call}} ADS.AddFailure_2(280, 1, sp)
    2 KB (267 words) - 18:24, 23 March 2017
  • This example assumes that a scheduled task with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get scheduled task #1 from project #1.}}
    2 KB (247 words) - 18:55, 9 June 2016
  • This example assumes that a corrective task with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get corrective task #1 from project #1.}}
    2 KB (247 words) - 18:55, 9 June 2016
  • {{APIComment|'Get a list of controls from project #1.}} MyRepository.Project.SetCurrentProject(1)
    1 KB (181 words) - 18:12, 2 March 2018
  • {{APIComment|'Get a list of actions from project #1.}} MyRepository.Project.SetCurrentProject(1)
    1 KB (181 words) - 18:12, 2 March 2018
  • ...der a sample of test units. A number of these units were obtained from Lot 1, others from Lot 2, and the rest from Lot 3. These three lots can be repres *Define two indicator variables, <math>{{X}_{1}}\,\!</math> and <math>{{X}_{2}}.\,\!</math>
    2 KB (369 words) - 23:58, 23 June 2015
  • {{APIPrefix|Call}} ads.AddFailure_2(245, 1, 353) {{APIPrefix|Call}} ads.AddFailure_2(110, 1, 373)
    3 KB (278 words) - 23:43, 6 September 2016
  • {{APIPrefix|Call}} ads.AddFailure_2(245, 1, 353) {{APIPrefix|Call}} ads.AddFailure_2(110, 1, 373)
    3 KB (278 words) - 23:43, 6 September 2016
  • ...dd the new item to project #1 and position it under system hierarchy item #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (259 words) - 17:49, 9 June 2016
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 1396|| 1|| 1396
    2 KB (263 words) - 20:54, 18 September 2023
  • {{APIComment|'Add the new effect to failure #1 located in project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (244 words) - 17:51, 9 June 2016
  • This example assumes that a spare part pool with ID #1 exists in the first project of a Synthesis repository. {{APIComment|'Get spare part pool #1 from project #1.}}
    2 KB (254 words) - 18:54, 9 June 2016
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| S||
    964 bytes (132 words) - 21:14, 18 September 2023
  • ...was tested and several failures occurred. The data set is given in columns 1 and 2 of the following table. Find the Logistic model that best fits the da {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
    3 KB (357 words) - 21:29, 18 September 2023
  • | F||1138||100||1 | F||1944||100||1
    3 KB (381 words) - 18:21, 28 September 2015
  • '''L8 (2^4 4^1)''' '''L16 (2^12 4^1)'''
    844 bytes (112 words) - 19:06, 15 September 2023
  • :<math> f(t)={ \frac{\beta }{\eta }}\left( {\frac{t}{\eta }}\right) ^{\beta -1}e^{-\left( { \frac{t}{\eta }}\right) ^{\beta }} \,\!</math> === The 1-Parameter Weibull===
    2 KB (262 words) - 15:36, 22 May 2023
  • !System 1 | 4.3||0.1||8.4
    2 KB (202 words) - 18:26, 28 September 2015
  • {{APIPrefix|Call}} ADS.AddFailure_2(100, 1, 190) {{APIPrefix|Call}} ADS.AddFailure_2(120, 1, 190)
    2 KB (214 words) - 20:30, 24 June 2016
  • {{APIPrefix|Call}} sp.AddSegment(1, 100) {{APIPrefix|Call}} ADS.AddFailure_2(61, 1, sp)
    3 KB (349 words) - 17:47, 5 May 2017
  • {{APIComment|'Get a list of causes for failure #1 from project #1.}} {{APIPrefix|Set}} Causes = MyRepository.Xfmea.GetAllXfmeaCauses(1)
    1 KB (129 words) - 18:48, 2 March 2018
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| F|| 1|| 0
    5 KB (567 words) - 21:29, 18 September 2023
  • !style="background:#f0f0f0;"|1 Table 6-1 from the book shows the ANOVA table for this experiment.
    1 KB (191 words) - 21:08, 18 September 2023
  • {{APIPrefix|Call}} WDS.AddFailure(10, 1) {{APIPrefix|Call}} WDS.AddFailure(20, 1)
    1 KB (166 words) - 17:40, 19 April 2016
  • ...'Add the new FMEA function to system hierarchy item #1 located in project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (274 words) - 18:51, 22 August 2016
  • ...the percent non-zero (Pnz) value of the data set. '''Double'''. A value of 1 indicates that there are no zero failure times in the data set; a decimal v {{APIPrefix|Call}} WDS.AddFailure(10, 1)
    2 KB (251 words) - 20:24, 24 June 2016
  • {{APIPrefix|Set}} listofsegments(1) = segment {{APIPrefix|Call}} ADS.AddFailure_2(252, 1, myProfile)
    3 KB (334 words) - 18:42, 23 March 2017
  • {{APIPrefix|Dim}} listOfSegments(1) {{APIPrefix|As}} SynthesisAPI.ProfileSegment segment.SegmentEnd = 1
    3 KB (276 words) - 22:18, 22 March 2017
  • :Optional. Double. The use stress level. Default value &#61; 1. {{APIPrefix|Call}} ADS.AddFailure_3(100, 1, 190, 235)
    2 KB (192 words) - 20:41, 24 June 2016
  • {{APIComment|'with beta &#61; 1 and eta &#61; 100. The model name is "MyNewModel."}} ModelParams(0) = 1
    3 KB (300 words) - 20:35, 18 August 2016
  • ...){{e}^{\pm {{z}_{\alpha }}\sqrt{Var(\widehat{R}(t))}/\left[ \widehat{R}(t)(1-\widehat{R}(t)) \right]}}}\,\!</math> {{[\widehat{R}(t)]}_{L}}= & {{[\widehat{R}(\tau )]}^{\tfrac{1}{{{\Pi }_{1}}}}} \\
    2 KB (278 words) - 21:23, 18 September 2023
  • {{APIComment|'Add the new cause to project #1, under effect #2 in failure #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (268 words) - 17:50, 9 June 2016
  • ...ith the following failure rates (in failures per hour): <math>{{\lambda }_{1}} = 0.0002\,\!</math>, <math>{{\lambda }_{2}} = 0.0005\,\!</math> and <mat {{R}_{s}}(t)= & {{R}_{1}}(t)\cdot {{R}_{2}}(t)\cdot {{R}_{3}}(t) \\
    3 KB (439 words) - 20:57, 18 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |3|| 4|| 1|| 25
    2 KB (321 words) - 21:21, 18 September 2023
  • & S{{S}_{A}}= & \underset{i=1}{\overset{{{n}_{a}}}{\mathop{\sum }}}\,{{n}_{b}}n{{({{{\bar{y}}}_{i..}}-{{{ & = & \underset{i=1}{\overset{{{n}_{a}}}{\mathop{\sum }}}\,\frac{y_{i..}^{2}}{{{n}_{b}}n}-\frac
    5 KB (802 words) - 19:07, 15 September 2023
  • ...bound on the required time to achieve the goal MTBF of 1,000 hours and the 1-sided 90% lower confidence bound on the MTBF at the end of the test time. T #Generate 1,000 data sets using SimuMatic along with the required output.
    3 KB (486 words) - 20:55, 18 September 2023
  • The data are from Example 11-1 on page 431 in the book ''Design and Analysis of Experiments'' by Douglas C | 8076.580||170||-1||-1||76.5
    2 KB (283 words) - 21:08, 18 September 2023
  • | style="width: 150px;"|MS_1Parameter||style="width: 80px;"|0||1-parameter form. |MS_2Parameter||1||2-parameter form.
    511 bytes (57 words) - 18:16, 24 June 2016
  • {{APIComment|'Get a list of causes for failure #1 from project #1.}} {{APIPrefix|Set}} Causes = MyRepository.Xfmea.GetAllXfmeaCauses(1)
    1 KB (135 words) - 18:48, 2 March 2018
  • | 1||F||252 | 1||F||315
    2 KB (286 words) - 16:18, 28 September 2015
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| F|| 0.3333
    3 KB (388 words) - 21:23, 18 September 2023
  • {{APIComment|'Get a list of all system hierarchy items in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (130 words) - 18:30, 9 June 2016
  • {{APIPrefix|Dim}} ModelParams(1) {{APIPrefix|As}} Double ModelParams(0) = 1
    1 KB (146 words) - 18:08, 3 April 2017
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 10|| 5
    2 KB (269 words) - 21:23, 18 September 2023
  • ...e reported on a particular date for a particular serialized system (Metric 1 only).</onlyinclude> :Required. Double. The value reported for Metric 1.
    544 bytes (64 words) - 23:03, 30 November 2017
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1||8||BD||1
    4 KB (571 words) - 20:53, 18 September 2023
  • ...internal models automatically created with any new repository (model ID#s 1 to 20).</onlyinclude> {{APIComment|'Get a list of all local models in project #1.}}
    2 KB (184 words) - 18:53, 9 June 2016
  • {{APIComment|'with beta &#61; 1 and eta &#61; 100. The model name is "MyNewModel."}} ModelParams(0) = 1
    3 KB (365 words) - 15:39, 28 April 2016
  • MyRepository.Project.SetCurrentProject(1) CrewIDs(0) = 1
    2 KB (241 words) - 22:09, 13 March 2019
  • MyRepository.Project.SetCurrentProject(1) CrewIDs(0) = 1
    2 KB (241 words) - 22:11, 13 March 2019
  • :<math>{{\lambda }_{i}}\left( t \right)=\lambda \beta {{t}^{\beta -1}}={{\lambda }_{c}}\left( t \right)\beta \,\!</math> :<math>{{\lambda }_{c}}\left( t \right)=\lambda {{t}^{\beta -1}}=\frac{{{\lambda }_{i}}\left( t \right)}{\beta }\,\!</math>
    2 KB (388 words) - 15:09, 14 February 2019
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac !Test Time Unit 1(hours)
    3 KB (354 words) - 21:21, 18 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac !Time Unit 1
    3 KB (463 words) - 20:53, 18 September 2023
  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1 ||F || 8
    2 KB (248 words) - 21:39, 18 September 2023
  • MyRepository.Project.SetCurrentProject(1) CrewIDs(0) = 1
    2 KB (260 words) - 22:40, 13 March 2019
  • {{APIPrefix|Call}} ADS.AddFailure_2(100, 1, 190) {{APIPrefix|Call}} ADS.AddFailure_2(120, 1, 190)
    2 KB (257 words) - 22:24, 4 May 2017
  • {{APIComment|'Add the new profile to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (181 words) - 23:14, 22 March 2017
  • {{APIComment|'Get a list of causes for failure #1 from project #1.}} {{APIPrefix|Set}} Causes = MyRepository.Xfmea.GetAllXfmeaCauses(1)
    1 KB (153 words) - 17:23, 5 March 2018
  • {{APIComment|'Get a list of causes for failure #1 from project #1.}} {{APIPrefix|Set}} Causes = MyRepository.Xfmea.GetAllXfmeaCauses(1)
    1 KB (153 words) - 17:22, 5 March 2018
  • For this example, Units 1 and 2 are the same component. Therefore, only one set of data was collecte \beta = & 1.9239 \\
    6 KB (909 words) - 19:43, 23 October 2012
  • {{APIPrefix|Call}} WDS.AddFailure(100, 1) {{APIPrefix|Call}} WDS.AddFailure(120, 1)
    2 KB (254 words) - 22:23, 4 May 2017
  • ...A model with a Weibull intensity function <math>\lambda \beta {{t}^{\beta -1}}\,\!</math>. It is not assumed that zero failures occurred during the gap ...,\!</math> and let <math>{{S}_{2}}<{{Y}_{1}}<{{Y}_{2}}<\ldots <{{Y}_{{{N}_{1}}}}\le T\,\!</math> be the failure times over <math>({{S}_{2}},\,T)\,\!</ma
    4 KB (533 words) - 21:15, 18 September 2023
  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
    3 KB (453 words) - 18:55, 18 September 2023
  • :<math>R = \frac{1}{1+be^{-kt}}, b > 0, k > 0, T \simeq 0</math> .../math> and an S-shaped curve will be generated. However, when <math>0<b\le 1\,\!</math> , then <math>{{T}_{i}}\le 0\,\!</math> and the Logistic reliabil
    3 KB (460 words) - 18:18, 29 May 2014
  • For example, consider a system whose RBDs for Phase 1 and Phase 2 are as shown in the figure below: [[Image:RBD for Phase 1 and 2.png|center|500px|link=]]
    5 KB (772 words) - 21:01, 18 September 2023
  • ::<math>\begin{align}SS_r = & \sum_{i=1}^n (y_i-\bar{y})^2 \\ = & \sum_{i=1}^n y_i^2-\frac{\left(\sum_{i=1}^n y_i\right)^2}{n}\end{align}\,\!</math>
    5 KB (777 words) - 19:08, 15 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac !System 1 ( <math>{{X}_{i1}}\,\!</math> )
    2 KB (302 words) - 21:15, 18 September 2023
  • ::<math>\sum_{i=1}^N (\hat{a}+\hat{b} x_i - y_i)^2=min(a,b)\sum_{i=1}^N (a+b x_i-y_i)^2 \,\!</math> ::<math>F=\sum_{i=1}^N (a+bx_i-y_i)^2 \,\!</math>
    7 KB (1,180 words) - 19:15, 15 September 2023
  • {{APIPrefix|Call}} wds.AddFailure(100, 1) {{APIPrefix|Call}} wds.AddFailure(120, 1)
    4 KB (418 words) - 23:41, 6 September 2016
  • ...the field are recorded. Both systems started operating from time 0. System 1 ends at time = 504 and system 2 ends at time = 541. All the BD modes are fi ...the future failures, what would be the expected number of failures at time 1,000?
    1 KB (173 words) - 20:54, 18 September 2023
  • ::<math>\mu ={{e}^{{\mu }'+\tfrac{1}{2}\sigma'^{2}}}\,\!</math> ...bar{T}} \right)-\frac{1}{2}\ln \left( \frac{\sigma^{2}}{{{{\bar{T}}}^{2}}}+1 \right)\,\!</math>
    4 KB (586 words) - 21:43, 18 September 2023
  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac | 1
    3 KB (403 words) - 18:55, 18 September 2023
  • CrewIDs(0) = 1 CrewIDs(1) = 4
    2 KB (229 words) - 16:07, 13 March 2019
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 35.50|| 38.48|| 38.14
    4 KB (473 words) - 21:30, 18 September 2023
  • ...ynamic) will be performed if the start of the maintenance phase is within (1-X)% of the scheduled time for the action. This helps in optimizing the reso ...on. In this phase, Block A fails every 750 hours while Block B fails every 1,300 hours. Corrective maintenance on Block A in this phase requires 100 hou
    5 KB (794 words) - 21:02, 18 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1||200 ||2||100.0||100
    5 KB (754 words) - 21:29, 18 September 2023
  • | 1||F||47154||337.15||10||1||1||F||29672||398.15||10||3 | 1||F||51307||337.15||10||1||1||F||38586||398.15||10||3
    7 KB (803 words) - 18:21, 28 September 2015
  • {{APIComment|'Get a list of all local variables in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (159 words) - 18:55, 9 June 2016
  • |Arrhenius||1||Arrhenius life-stress relationship, Reciprocal X &#61; 1/V transformation.
    647 bytes (73 words) - 22:17, 20 April 2016
  • This example assumes that a system hierarchy item with record ID #1 exists in the first available project in a repository. {{APIComment|'Get a list of all items in the system hierarchy in project #1.}}
    2 KB (234 words) - 18:47, 9 June 2016
  • {{APIComment|'Get a list of all profiles in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (159 words) - 23:14, 22 March 2017
  • {{APIComment|'Get a list of all actions in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (158 words) - 18:52, 9 June 2016
  • ...s reported on a particular date for a particular serialized system (Metric 1 and 2).</onlyinclude> :Required. Double. The value reported for Metric 1.
    632 bytes (75 words) - 23:04, 30 November 2017
  • {{APIComment|'Add the new control to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (203 words) - 16:41, 9 June 2016
  • | 1||384||F||788||523.15 ::<math>\mu' = \beta_{0}+\beta_{1} \times \frac{11605}{T}\,\!</math>
    4 KB (563 words) - 18:18, 28 September 2015
  • {{APIComment|'Get a list of all local crews in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (159 words) - 18:52, 9 June 2016
  • {{APIComment|'Get a list of all local URDs in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (161 words) - 18:55, 9 June 2016
  • {{APIComment|'Get a list of all Xfmea controls in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (160 words) - 18:52, 9 June 2016
  • {{APIPrefix|Call}} ADS.AddSuspension_2(100, 1, 190) {{APIPrefix|Call}} ADS.AddSuspension_2(120, 1, 190)
    3 KB (286 words) - 23:42, 22 March 2017
  • {{APIComment|'Get a list of all local models in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (159 words) - 18:53, 9 June 2016
  • ...is, in fact, a special case of the Weibull distribution where <math>\beta =1\,\!</math>. The exponential distribution is used to model the behavior of u *The scale parameter is <math>\tfrac{1}{\lambda }=\bar{t}-\gamma =m-\gamma \,\!</math>.
    4 KB (539 words) - 00:23, 9 March 2023
  • segment.SegmentEnd = 1 {{APIPrefix|Set}} listOfSegments(1) = segment
    5 KB (491 words) - 23:28, 22 March 2017
  • {{APIComment|'Get a list of all local corrective tasks in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (162 words) - 18:54, 9 June 2016
  • {{APIComment|'Get a list of all local scheduled tasks in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (161 words) - 18:54, 9 June 2016
  • {{APIPrefix|Call}} ADS.AddSuspension_2(100, 1, 190) {{APIPrefix|Call}} ADS.AddSuspension_2(120, 1, 190)
    3 KB (292 words) - 17:47, 5 May 2017
  • {{template:LDABOOK|14.1|Logistic Confidence Bounds}} ...qrt{2\pi }}\int_{{{K}_{\alpha }}}^{\infty }{{e}^{-\tfrac{{{t}^{2}}}{2}}}dt=1-\Phi ({{K}_{\alpha }})\,\!</math>
    5 KB (672 words) - 00:59, 10 March 2023
  • {{APIPrefix|Call}} ADS.AddFailure_2(100, 1, 190) {{APIPrefix|Call}} ADS.AddFailure_2(120, 1, 190)
    3 KB (293 words) - 19:39, 10 August 2018
  • {{APIComment|'Add the new action to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (210 words) - 15:34, 9 June 2016
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| F|| 2
    2 KB (278 words) - 21:22, 18 September 2023
  • {{APIComment|'Get a list of all local spare part pools in project #1.}} MyRepository.Project.SetCurrentProject (1)
    1 KB (164 words) - 18:54, 9 June 2016
  • {{APIPrefix|Call}} ADS.AddFailure_2(100, 1, 190) {{APIPrefix|Call}} ADS.AddFailure_2(120, 1, 190)
    3 KB (299 words) - 17:46, 5 May 2017
  • ...{\lambda }}_{CA}}=\widehat{\lambda }\widehat{\beta }{{T}^{\widehat{\beta }-1}}=0.12744\,\!</math> :<math>MTB{{F}_{D}}={{[{{\hat{\lambda }}_{D}}(T)]}^{-1}}=7.84708\,\!</math>
    5 KB (711 words) - 21:31, 18 September 2023
  • | 1||5||14 | 1||0.667
    1 KB (147 words) - 18:26, 28 September 2015
  • To demonstrate a reliability of 97% at 1,000 hours with 50% confidence, 15 samples are tested for a zero failure tes The book shows that the units should be tested for 1,232 hours.
    787 bytes (109 words) - 16:25, 28 September 2015
  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
    1 KB (168 words) - 07:09, 20 August 2012
  • {{APIComment|'Add the new crew to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (235 words) - 20:34, 18 August 2016
  • {{APIComment|'Add the new URD to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (237 words) - 20:37, 18 August 2016
  • WDS.AddFailure(1, 1) WDS.AddFailure(2, 1)
    2 KB (227 words) - 15:11, 3 August 2017
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 2.7|| 0.99325
    2 KB (242 words) - 21:21, 18 September 2023
  • {{APIComment|'Add the new variable to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (234 words) - 20:37, 18 August 2016
  • '''1-Parameter Exponential Probability Plot Example''' ...imes are 7, 12, 19, 29, 41, and 67 hours. Estimate the failure rate for a 1-parameter exponential distribution using the probability plotting method.
    2 KB (289 words) - 21:44, 18 September 2023
  • {{APIComment|'Add the new task to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (238 words) - 20:36, 18 August 2016
  • {{APIComment|'Add the new task to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (240 words) - 20:36, 18 August 2016
  • {{APIPrefix|Call}} ads.AddFailure_2(245, 1, 353) {{APIPrefix|Call}} ads.AddFailure_2(110, 1, 373)
    4 KB (450 words) - 23:43, 6 September 2016
  • MyRepository.Project.SetCurrentProject(1) {{APIComment|'Get block #1 from diagram #21 in the project.}}
    3 KB (282 words) - 23:30, 6 September 2016
  • ...s reported on a particular date for a particular serialized system (Metric 1, 2 and 3).</onlyinclude> :Required. Double. The value reported for Metric 1.
    723 bytes (86 words) - 23:04, 30 November 2017
  • | 1||384||F||788||523.15 ::<math>\mu' = \beta_{0}+\beta_{1} \times \frac{11605}{T}\,\!</math>
    3 KB (401 words) - 18:19, 28 September 2015
  • ...}_{1}}\le {{X}_{2}}]=\frac{1}{{{F}_{1}}(U)-{{F}_{1}}(L)}\int_{L}^{U}{{{f}_{1}}(x)\cdot {{R}_{2}}(x)}dx\,\!</math> :: <math>L\le {{X}_{1}}\le U\,\!</math>
    7 KB (1,112 words) - 19:11, 15 September 2023
  • {{APIComment|'Add the new spare part pool to project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (244 words) - 20:35, 18 August 2016
  • {|border="1" cellpadding="5" cellspacing="0" style="border-collapse: collapse; text-ali ...he numeric ID of the variable resource for Parameter 2, then set Parameter 1 to zero (0) or nothing. If the variable does not exist, it creates a dynami
    3 KB (368 words) - 15:14, 3 August 2017
  • {{APIComment|'Get model #47 from project #1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (240 words) - 20:34, 18 August 2016
  • A reliability growth data set is given in columns 1 and 2 of the following table. Find the modified Gompertz curve that represe {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
    6 KB (737 words) - 21:31, 18 September 2023
  • ::<math>F(T)=1-{{e}^{-{{\left( \tfrac{T}{\eta } \right)}^{\beta }}}}\,\!</math> R(T)= & 1-F(t) \\
    2 KB (345 words) - 19:24, 15 September 2023
  • {{APIPrefix|Call}} ADS.AddSuspensionInterval_2(100, 120, 1, 190) {{APIPrefix|Call}} ADS.AddSuspensionInterval_2(120, 130, 1, 190)
    3 KB (309 words) - 23:48, 22 March 2017
  • f(x;{{\theta }_{1}},{{\theta }_{2}},...,{{\theta }_{k}}), ...riment and obtain <math>N\,\!</math> independent observations, <math>{{x}_{1}},\,\!</math> <math>{{x}_{2}},\,\!</math><math>...,\,\!</math> <math>{{x}_{
    8 KB (1,122 words) - 19:13, 15 September 2023
  • {{APIPrefix|Call}} WDS.AddFailure(1, 1) {{APIPrefix|Call}} WDS.AddFailure(2, 1)
    2 KB (238 words) - 16:29, 24 June 2016
  • {{APIComment|'Delete model #71 from project #1.}} MyRepository.Project.SetCurrentProject(1)
    925 bytes (111 words) - 17:25, 8 April 2016
  • {{APIComment|'Connect to project #1 in the repository.}} MyRepository.Project.SetCurrentProject (1)
    2 KB (219 words) - 23:32, 6 September 2016
  • \text{400} & \text{1/1/2005} & \text{Model A} \\ \text{500} & \text{1/31/2005} & \text{Model A} \\
    7 KB (811 words) - 18:54, 18 September 2023
  • {{APIPrefix|Call}} ADS.AddSuspensionInterval_2(100, 120, 1, 190) {{APIPrefix|Call}} ADS.AddSuspensionInterval_2(120, 130, 1, 190)
    3 KB (315 words) - 17:47, 5 May 2017
  • = & \gamma +\frac{1}{\lambda }=m ::<math> \breve{T}=\gamma +\frac{1}{\lambda}\cdot 0.693 \,\!</math>
    4 KB (570 words) - 21:41, 18 September 2023
  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
    1 KB (176 words) - 05:57, 20 August 2012
  • :Optional. Double. The duty cycle. Default value = 1. {{APIComment|'Get model ID #47 from project ID #1 in the repository.}}
    2 KB (267 words) - 19:01, 18 August 2016
  • ...aining <math>B\,\!</math> events are halved. Determine the reliability at 1,000 hours for this component. ::<math>{{\mu }_{1}}= \frac{1}{KV_{1}^{n}}\ \,\!</math>
    5 KB (802 words) - 21:00, 18 September 2023
  • ...rst stress in the model has an index = 0, the second stress has an index = 1, etc.). This example assumes that an ALTA model with ID #47 exists in project ID #1 of a repository.
    4 KB (476 words) - 21:17, 13 November 2015
  • |1||F||245||353 |1||F||110||373
    6 KB (762 words) - 18:49, 3 April 2017
  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
    1 KB (179 words) - 23:43, 20 August 2012
  • ...epair rates both follow exponential distributions with a failure rate of 0.1 failures per hour and a repair rate of 0.2 repairs per hour. |Component 1||0.1||0.2
    4 KB (635 words) - 16:35, 20 August 2015
  • :<math>f=1-{{(1-CL)}^{\tfrac{1}{{{S}_{n}}}}}\,\!</math> ..., after one successful test following a corrective action, <math>{{S}_{n}}=1\,\!</math>, the failure is given a value of 0.9 based on a 90% confidence l
    2 KB (318 words) - 20:39, 18 September 2023
  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
    1 KB (177 words) - 07:16, 20 August 2012
  • *Configuration 1 experienced 5 failures, {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
    2 KB (192 words) - 21:16, 18 September 2023
  • ...he observed reliability given and <math>{{n}_{k}}\,\!</math> is considered 1. :<math>{{L}_{k}}=const.\text{ }R_{k}^{{{S}_{k}}}{{(1-{{R}_{k}})}^{{{n}_{k}}-{{S}_{k}}}}\,\!</math>
    13 KB (1,948 words) - 22:55, 3 June 2014
  • \begin{bmatrix}122.43 & 333.64\\ 333.64 & 967.68\end{bmatrix}^{-1} & = \begin{bmatrix}Var(\hat{\lambda}) & Cov(\hat{\beta},\hat{\lambda})\\ ...{{\lambda }_{c}}(T)}{\partial \beta }= & \hat{\lambda }{{T}^{\hat{\beta }-1}}\ln (T) \\
    10 KB (1,186 words) - 21:31, 18 September 2023
  • *[http://www.reliawiki.org/index.php/1P_Exponential_Example 1-Parameter Exponential Example]
    466 bytes (60 words) - 04:32, 13 August 2012
  • {{APIPrefix|Dim}} myarray(1) {{APIPrefix|As PoolInfo}} myarray(1).ID = 4
    1 KB (171 words) - 17:03, 4 May 2020
  • {{APIPrefix|Dim}} myarray(1) {{APIPrefix|As PoolInfo}} myarray(1).ID = 4
    1 KB (171 words) - 17:02, 4 May 2020
  • \text{96} & \text{1} \\ \text{1,051} & \text{5} \\
    3 KB (465 words) - 18:33, 18 September 2023
  • ::<math>f(t)=\frac{{{e}^{z}}}{\sigma {t}{{(1+{{e}^{z}})}^{2}}}\,\!</math> ::<math>\overline{T}={{e}^{\mu }}\Gamma (1+\sigma )\Gamma (1-\sigma )\,\!</math>
    9 KB (1,321 words) - 17:12, 23 December 2015
  • | 49||157.1 | 99||157.1
    3 KB (399 words) - 18:19, 28 September 2015
  • ...[\frac{E\left(R_{0}\right)-E^{2}\left(R_{0}\right)}{Var\left(R_{0}\right)}-1\right]=127.0794\,\!</math> ...[\frac{E\left(R_{0}\right)-E^{2}\left(R_{0}\right)}{Var\left(R_{0}\right)}-1\right]=20.40153\,\!</math>
    3 KB (493 words) - 18:55, 18 September 2023
  • {{APIComment|'Get model #47 from project#1.}} MyRepository.Project.SetCurrentProject(1)
    2 KB (242 words) - 18:53, 9 June 2016
  • #If <math>\beta <1\,\!</math>, would it be cost-effective to implement an overhaul policy? {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
    2 KB (240 words) - 20:54, 18 September 2023
  • Determine the reliability at 1,000 hours for this component. ...iner with weight proportionality factors of 1, 2 and 3 respectively (and a 1-out-of-3 requirement).
    4 KB (603 words) - 20:04, 23 October 2012
  • :Optional. Double. The duty cycle. Default value = 1. {{APIComment|'Get model ID #47 from project ID #1 in the repository.}}
    3 KB (285 words) - 19:02, 18 August 2016
  • |1||F||16 |1||F||34
    5 KB (619 words) - 18:43, 3 April 2017
  • {{APIPrefix|Call}} WDS.AddFailure(100, 1) {{APIPrefix|Call}} WDS.AddFailure(120, 1)
    3 KB (377 words) - 16:07, 17 August 2016
  • :Optional. Double. The duty cycle. Default value = 1. {{APIComment|'Get model ID #47 from project ID #1 in the repository.}}
    3 KB (278 words) - 16:03, 23 September 2016
  • | 1||0.7 ...BD modes: CVM = 0.085, critical value = 0.171 with significance level = 0.1. Since CVM < critical value can fail to reject hypothesis that the model fi
    3 KB (392 words) - 18:26, 28 September 2015
  • ...in a system failure (which for the case of non-redundancy or if in series =1). ...\frac{\frac{Q{{(t)}_{{{mode}_{i}}}}}{Q{{(t)}_{Component}}}}{\sum\limits_{i=1}^{M}{\frac{Q{{(t)}_{{{mode}_{i}}}}}{Q{{(t)}_{Component}}}}}\,\!</math>
    7 KB (1,111 words) - 05:19, 23 August 2012
  • ...We will assume a Weibull distribution with a shape parameter <math>\beta =1.5\,\!</math>. We want to determine the number of units to test for <math>{{ ::<math>MTTF=\eta \cdot \Gamma (1+\frac{1}{\beta })\,\!</math>
    2 KB (360 words) - 18:55, 18 September 2023
  • ...sign and Test – Statistical Test and Estimation Methods), Example 2 – Case 1, pg. 30. *Beta(UnB) = 0.5594, Lambda = 1.1067
    2 KB (235 words) - 18:27, 28 September 2015
  • ...s to estimate the reliability of the component within the warranty period (1 year/15,000 miles). {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
    5 KB (554 words) - 18:53, 18 September 2023
  • ...th parameters α = 35,800 hours (this is the eta value in BlockSim) and β = 1.35. We calculate the reliability of the system after 8760 hours of use, and ...}\right)^{\beta} \right ] = exp\left [ -\left(\frac{8,760}{35,800}\right)^{1.35} \right ] = 0.8611\,\!</math>
    3 KB (442 words) - 17:12, 31 July 2015
  • :Optional. Double. The duty cycle. Default value = 1. {{APIComment|'Get model ID #47 from project ID #1 in the repository.}}
    3 KB (282 words) - 19:01, 18 August 2016
  • ...ator variable that takes a discrete value of 0 for an on/off operation and 1 for a continuous operation. The following figure shows the stress types and ::<math>\eta ={{e}^{{{\alpha }_{0}}+{{\alpha }_{1}}\tfrac{1}{{{V}_{1}}}+{{\alpha }_{2}}\ln ({{V}_{2}})+{{\alpha }_{3}}{{V}_{3}}}}\,\!</math>
    4 KB (644 words) - 19:03, 18 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |F||1||8||BD||1
    7 KB (930 words) - 20:53, 18 September 2023
  • :<math>\hat{b}=1.9453\,\!</math> ...p \sum }}\,{{(\ln {{t}_{i}})}^{2}} \right]-\frac{1}{n}{{\left( \underset{i=1}{\overset{n}{\mathop \sum }}\,\ln ({{t}_{i}}) \right)}^{2}} \\
    4 KB (503 words) - 21:23, 18 September 2023
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| F
    1 KB (160 words) - 21:17, 18 September 2023
  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
    1 KB (195 words) - 07:03, 20 August 2012
  • :Optional. Double. The duty cycle. Default value = 1. {{APIComment|'Get model ID #47 from project ID #1 in the repository.}}
    3 KB (288 words) - 19:02, 18 August 2016
  • {{APIPrefix|Call}} sp.AddSegment(1, 250) sp.AddSegment(1, 250)
    1,003 bytes (100 words) - 22:04, 23 March 2017
  • R=1-{{\Gamma }_{I}}(k;{{e}^{z}}) The mode exists if <math>k>1\,\!</math> and is given by:
    8 KB (1,229 words) - 17:10, 23 December 2015
  • #After estimating the parameters, verify the assumption of <math>\beta = 1\,\!</math>. {|width="350" border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
    3 KB (367 words) - 21:35, 18 September 2023
  • :<math>{{u}_{q}}(t)={{\lambda }_{q}}{{\beta }_{q}}{{t}^{{{\beta }_{q}}-1}}\,\!</math> ...tes the hypothesis, <math>{{H}_{o}}\,\!</math>, such that <math>{{\beta }_{1}}={{\beta }_{2}}=\ldots ={{\beta }_{K}}\,\!</math>. Let <math>{{\tilde{\bet
    8 KB (1,083 words) - 20:40, 18 September 2023
  • The data set from Example 14.1 on page 348 in the book ''Statistical Methods for Reliability Data'' by Dr. | 1||F||230
    3 KB (440 words) - 16:21, 28 September 2015
  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1 ||F||2
    8 KB (870 words) - 21:46, 18 September 2023
  • {{APIPrefix|Call}} SP.AddSegment(1, 250) SP.AddSegment(1, 250)
    1 KB (112 words) - 22:05, 23 March 2017
  • <math>E(\text{Cost Per Cycle})={{C}_{P}}R(x)+{{C}_{U}}\left( 1-R(x) \right)</math> ...}{E\left( \text{Cycle Length} \right)}=\frac{{{C}_{P}}R(x)+{{C}_{U}}\left( 1-R(x) \right)}{\int_{0}^{x}{R(t)dt}}</math>
    7 KB (1,243 words) - 19:16, 15 September 2023
  • ...}_{D}}(T)-{{\lambda }_{D}}(T)}{\sqrt{{{\lambda }_{D}}(T)}} \right)\sim N(0,1)\,\!</math> where <math>C=\tfrac{{{z}_{1-\alpha /2}}}{\sqrt{T}}\,\!</math>.
    10 KB (1,494 words) - 20:41, 18 September 2023
  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
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  • <li>The next figure illustrates the application of rule #1 for mode BD1. The mode in the equivalent single system is calculated as <ma The next figure illustrates the application of rule #1 for mode A110. The mode in the equivalent single system is calculated as <m
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  • ...mean time to occurrence of 1,000 hours (i.e., exponential with <math>MTTF=1,000).\,\!</math> <br> ...exponential with <math>MTT{{F}_{B}}=700,000\,\!</math>, <math>MTT{{F}_{C}}=1,000,000\,\!</math> and <math>MTT{{F}_{F}}=2,000,000).\,\!</math> <br>
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  • | style="width: 200px;"|AllowExponential1||Indicates whether the 1-parameter exponential distribution will be considered. '''Boolean'''. Defau {{APIPrefix|Call}} WDS.AddFailure(10, 1)
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  • ...nches given in the first table below, the first failure was caused by Mode 1, the second and fourth failures were caused by Mode 2, the third and fifth {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
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  • ...include one, then you can fail to reject the hypothesis that <math>\beta = 1\,\!</math>.
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 1|| 66|| 4.190
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 2|| 200|| 5.298|| 28.072|| 0.693|| 3.673
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| .67
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  • {{APIComment|'Check whether model #42 from project #1 is in use.}} MyRepository.Project.SetCurrentProject(1)
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  • == Part 1 Assumptions/Deviations == 1. ReliaSoft added area consequence to PRDs when failure to open occurs, sinc
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  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
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  • ...eta }{\Gamma (k)\cdot \theta }{{\left( \frac{t}{\theta } \right)}^{k\beta -1}}{{e}^{-{{\left( \frac{t}{\theta } \right)}^{\beta }}}}\,\!</math> ::<math>\Gamma (x)=\int_{0}^{\infty }{{{s}^{x-1}}}\cdot {{e}^{-s}}ds\,\!</math>
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  • *The growth potential design margin factor is <math>GPDM=1.35\,\!</math>. ...00\,\!</math> hours. The average fix delays for each phase are <math>{{L}_{1}}=500\,\!</math>, <math>{{L}_{2}}=700\,\!</math> and <math>{{L}_{3}}=1000
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  • ...otal number of BD failures during the test is <math>{{N}_{BD}}=\underset{j=1}{\overset{M}{\mathop{\sum }}}\,{{N}_{j}}\,\!</math>. These values and effec {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
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  • {{APIPrefix|Dim}} myarray(1) {{APIPrefix|As Long}} myarray(1) = 4
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  • {{APIPrefix|Dim}} myarray(1) {{APIPrefix|As Long}} myarray(1) = 4
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 38
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  • :* The cost for a preventive replacement is $1.<br> = & \frac{{{C}_{P}}\cdot R\left( t \right)+{{C}_{U}}\cdot \left[ 1-R\left( t \right) \right]}{\int_{0}^{t}R\left( s \right)ds}
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  • |1||F||252 |1||F||280
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  • ...y for both designs is assumed to follow a Weibull distribution. For Design 1, its shape parameter <math>\beta = 3\,\!</math>; for Design 2, its <math>\b ...s 2 for cell (1000, 2000). This means that if the B10 life for Design 1 is 1,000 hours and the B10 life for Design 2 is 2,000 hours, the difference can
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  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
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  • {{APIPrefix|Dim}} myarray(1) {{APIPrefix|As Long}} myarray(1) = 4
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  • ...ponent in order to demonstrate a B10 life of 1 year with a 90% confidence (1-sided limit). The engineer has 3 months available for testing and wants to ...the use stress level. Therefore he sets the characteristic life at 400K as 1/40th of the calculated characteristic life at 300K as shown in the next fig
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  • MyRepository.Project.SetCurrentProject(1) Dict = MyRepository.Xfmea.GetAllXfmeaCausesDictionary(1)
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  • ...to-failure that are described by a Weibull distribution with <math>\beta = 1.318\,\!</math> and <math>\eta = 312\,\!</math> hours. All three components *'''Case 2''' - Same as in Case 1, but Component 1 has a feasibility of Easy, Component 2 has a feasibility of Moderate and Co
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  • [[Image:Lda11.1.png|center|400px]] ...population has accumulated 0 recurrences, another fraction has accumulated 1 recurrence, another fraction has accumulated 2 recurrences, etc. This distr
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  • {{APIComment|'Import the data from the XML file into project #1 in the repository.}} MyRepository.Project.SetCurrentProject(1)
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  • ...of a vector of <math>n\,\!</math> stresses, or <math>\underline{X}=({{X}_{1}},{{X}_{2}}...{{X}_{n}}).\,\!</math> ALTA includes this relationship and al ::<math>L(\underline{X})={{e}^{{{\alpha }_{0}}+\underset{j=1}{\overset{n}{\mathop{\sum }}}\,{{\alpha }_{j}}{{X}_{j}}}}\,\!</math>
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  • ...ln (\beta )}{\sqrt{Var\left[ \ln (\hat{\beta }) \right]}}\ \tilde{\ }\ N(0,1)\,\!</math> ...{S}_{q}}) \right]-\underset{q=1}{\overset{K}{\mathop{\sum }}}\,\underset{i=1}{\overset{{{N}_{q}}}{\mathop{\sum }}}\,\ln ({{X}_{i}}{{}_{q}})}\,\!</math>
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  • ...sum^{n}_{i=k}\frac{1}{i} = \frac{1}{2.7 \times 10^{-5}}\sum^{5}_{i=3}\frac{1}{i} = 2.9 \times 10^{4}\,\!</math> &nbsp; hours ::<math>R(t) = \sum^{n}_{i=k}C^{i}_{n} e^{-\lambda i t} (1-e^{-\lambda t})^{n-i}\,\!</math>
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  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
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  • ...{{\left( \tfrac{{{T}_{i}}}{\eta } \right)}^{\beta }}}} \right]-\underset{i=1}{\overset{S}{\mathop \sum }}\,N_{i}^{\prime }{{\left( \frac{T_{i}^{\prime } & \text{ }+\underset{i=1}{\overset{FI}{\mathop \sum }}\,N_{i}^{\prime \prime }\ln \left[ {{e}^{-{{\l
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  • {| class="FCK__ShowTableBorders" border="0" cellspacing="1" cellpadding="1"
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  • MyRepository.Project.SetCurrentProject(1) Dict = MyRepository.Xfmea.GetAllXfmeaFailuresDictionary(1)
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  • |Computer 1||5.5 x 10<sup>-6</sup> R(t)&=[1-(1-R_{C1})(1-R_{C3})]R_{C2}+R_{C3}R_{C4}(1-R_{C2})\\
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  • ...SCLUDED IN PAGE: Duane Model Examples. IF YOU EDIT THE DATA SET IN EXAMPLE 1, YOU MUST ALSO EDIT THE DATA SET AND RESULTS ON THE FOLLOWING PAGES: Duane ==Example 1==
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  • ...is assumed to follow a uniform distribution. '''Double'''. Default value = 1. ...is assumed to follow a normal distribution. '''Double'''. Default value = 1.
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  • {{APIComment|'Export the data from project #1 in the repository. Name the file "MyBlockSimData.xml" and save it in the C: MyRepository.Project.SetCurrentProject(1)
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  • ...lowing parameters, <math>{{\beta }_{1}}=1.5\,\!</math> and <math>{{\eta }_{1}}=5000\,\!</math>. For the hard drive, the parameters are <math>{{\beta }_ ...}}(365)= & {{e}^{-{{\left( \tfrac{365}{{{\eta }_{1}}} \right)}^{{{\beta }_{1}}}}}} \\
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  • |Body||5.1 x 10<sup>-4</sup> Substituting the values of <math>\lambda_{1}</math>, <math>\lambda_{2}</math>, <math>\lambda_{3}</math>, and <math>\lam
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  • ...ln \hat{\beta }-\ln \beta }{\sqrt{Var(\ln \hat{\beta }})}\ \tilde{\ }\ N(0,1)\,\!</math> ...<math>\alpha \,\!</math> ) according to a 2-sided confidence interval or a 1-sided confidence interval, and variances can be calculated using the Fisher
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  • ::<math>f({t}')=\frac{1}{{{\sigma' }}\sqrt{2\pi }}{{e}^{-\tfrac{1}{2}{{\left( \tfrac{{{t}^{\prime }}-{\mu }'}{{{\sigma' }}} \right)}^{2}}}}\, f(t)= & \frac{1}{t\cdot {{\sigma' }}\sqrt{2\pi }}{{e}^{-\tfrac{1}{2}{{\left( \tfrac{\text{ln}(t)-{\mu }'}{{{\sigma' }}} \right)}^{2}}}}
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 33.35
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  • ...mbel distribution with <math>\mu =\ln (\eta )\,\!</math> and <math>\sigma =1/\beta )\,\!</math>. & \hat{\sigma }= & 1.9717
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  • MyRepository.Project.SetCurrentProject(1) Dict = MyRepository.Xfmea.GetAllXfmeaEffectsDictionary(1)
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  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1 ||500
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  • 1) Using the T-NT Weibull model, analyze the data and determine the MTTF and 1. Analyze the data set in the ALTA standard folio and use the Quick Calculat
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  • The data set is from Example 8.1 on page 336 in the book ''Life Cycle Reliability Engineering'' by Dr. Guang !1
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  • | 208||80||120||1 ...pha _{0}+\alpha _{1}ln\left ( \Delta T \right )+\alpha _{3}ln\left ( \frac{1}{T_{MAX}} \right )\\
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  • {{APIPrefix|Call}} sp.AddSegment(1, 250) sp.AddSegment(1, 250)
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  • \text{7}\text{.8} & \text{99}\text{.2} & \text{151} & \text{260}\text{.1} & \text{342} & \text{430}\text{.2} \\ \text{17}\text{.6} & \text{99}\text{.6} & \text{163} & \text{273}\text{.1} & \text{350}\text{.2} & \text{445}\text{.7} \\
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  • ...le component was improved. In other words, it was observed that Component 1 had the largest reliability importance in the system relative to the other ::<math>{{R}_{_{S}}}={{R}_{1}}\cdot {{R}_{2}}\cdot {{R}_{3}} \ \,\!</math>
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  • Given <math>n\,\!</math> time-varying stresses <math>\underline{X}=({{X}_{1}}(t),{{X}_{2}}(t)...{{X}_{n}}(t))\,\!</math>, the life-stress relationship ...}}\, \right)}=s(t,\overset{\_}{\mathop{x}}\,)={{e}^{-{{a}_{0}}-\underset{j=1}{\mathop{\overset{n}{\mathop{\mathop{\sum}_{}^{}}}\,}}\,{{a}_{j}}{{x}_{j}}(
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  • | style="width: 150px;"|English||style="width: 70px;"|1
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  • [[Image:ALTA12.1.gif|center|550px|Step profile for a simple voltage stress test.]] ::<math>\eta(V)=\frac{1}{{{K}{V}}^\eta } \,\!</math>
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  • |KaplanMeier||1||Kaplan-Meier estimator.
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  • MyRepository.Project.SetCurrentProject(1) Dict = MyRepository.Xfmea.GetAllXfmeaFunctionsDictionary(1, {{APIPrefix|True)}}
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  • f(t)=\tfrac{{{e}^{z}}}{\sigma {{(1+{{e}^{z}})}^{2}}} \\ \\ ::<math>R(t)=\frac{1}{1+{{e}^{z}}}\,\!</math>
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |colspan="4" style="text-align:center"|Table B.1- The Test Data
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  • ...We will assume a Weibull distribution with a shape parameter <math>\beta =1.5\,\!</math>. ::<math>\eta =\frac{{{t}_{DEMO}}}{{{(-\text{ln}({{R}_{DEMO}}))}^{\tfrac{1}{\beta }}}}\,\!</math>
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 1137 BD1, 1268 BD2
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  • ...lambda }_{D}}(T)]}_{L}} = & {{\widehat{\lambda }}_{D}}(T)\frac{\chi _{(2N,1-\alpha /2)}^{2}}{2N} \\ \hat{\lambda_{p}} &= \frac{N_{i}}{T}+\sum_{i=1}^{M}(1-d_{i})\frac{N}{T}+\overline{d}\left(\frac{M}{T}\overline{\beta} \right )\\
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  • ::<math>f(t)=\frac{1}{\sigma \sqrt{2\pi }}{{e}^{-\frac{1}{2}{{\left( \frac{t-\mu }{\sigma } \right)}^{2}}}}\,\!</math> ...y }f(x)dx=\int_{t}^{\infty }\frac{1}{{{\sigma }}\sqrt{2\pi }}{{e}^{-\tfrac{1}{2}{{\left( \tfrac{x-\mu }{{{\sigma }}} \right)}^{2}}}}dx\,\!</math>
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  • ...eEnum]]''', which specifies the effect of the restoration. Default value = 1 (restores all accumulated damage). ...cates an as bad as old condition. A values greater than zero but less than 1 indicates a partial restoration. '''Double'''.
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  • :<math>f=\lambda {{t}^{\beta }}-\lambda {{\left( t-1 \right)}^{\beta }}\,\!</math> :<math>{{f}_{GP}}={{f}_{A}}+\left( 1-d \right){{f}_{B}}\,\!</math>
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  • ===Case 1=== ...Change Trigger Example Case 1.png|center|450px| Behavior of system in Case 1]]
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  • ==Level 1== ...mited to single phase systems of the select representative fluids. A level 1 analysis is performed by ReliaSoft's RBI software. Area and financial conse
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  • ...=\frac{1}{\sqrt{2\pi }}\int_{K_{\alpha }}^{\infty }e^{-\frac{t^{2}}{2} }dt=1-\Phi (K_{\alpha }) \,\!</math> ...ha =\frac{1-\delta }{2} \,\!</math> for the two-sided bounds and <math>a = 1 - d\,\!</math> for the one-sided bounds. The variances and covariances of <
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  • ...s the number of spares added per emergency. '''Integer'''. Default value = 1. ...ly when the UseFixedProbability property is set to true. Default value = 0.1.
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  • {{template:LDABOOK|7.1|Exponential Parameter Estimation}} F(t)=1-{{e}^{-\lambda (t-\gamma )}}
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  • |LikelihoodRatio||1||Likelihood ratio
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  • |RRY||1||Rank regression on Y.
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  • |Exponential||1||Exponential distribution
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  • ::<math>L(x(t))={{e}^{{{\alpha }_{0}}+{{\alpha }_{1}}\tfrac{1}{x(t)}}}\,\!</math> {{\alpha }_{1}}=\ & b
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 0 - 62|| 12
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  • {{R}_{5}}= & \frac{1}{1+b{{e}^{-5k}}} \\
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  • WDS.AddFailure(16, 1) WDS.AddFailure(34, 1)
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  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac | 1 || F || 1180
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  • ...math> through <math>E\,\!</math> are Weibull distributed with <math>\beta =1.2\,\!</math> and <math>\eta =1230\,\!</math> hours. The starting and endin ...blocks cannot fail, <math>{{R}_{Start}}=1\,\!</math> and <math>{{R}_{End}}=1,\,\!</math> the equation above can be reduced to:
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  • {{\alpha }_{1}}=\ & b ::<math>\frac{1}{m(t,x)}=s(t,x)=\frac{{{e}^{-bx(t)}}}{C}\,\!</math>
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  • ...cessive <math>N=86\,\!</math> failure times that were reported for <math>T=1,000\,\!</math> hours of testing. <center><math>{{X}_{i}},\,\!</math> <math>i=1,2,\ldots ,86\,\!</math>, <math>N = 86, T = 1000\,\!</math></center>
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  • & Q=1-{{e}^-{{{\left( \frac{t}{\eta } \right)}^{\beta }}}}\Rightarrow \\ & \ln (1-Q)={{\left( \frac{t}{\eta } \right)}^{\beta }} \\
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1 ||80
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  • {{APIPrefix|Call}} SP.AddSegment(1, 250) SP.AddSegment(1, 250)
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  • ...eliability of the landing gears follows a Weibull distribution with Beta = 1.5 and Eta = 15 hours. #At time 6.41 hours, in the Cruising phase, Engine 1 fails too. This failure brings the system down and the system goes into the
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  • ::<math>\underline{X}=({{x}_{1}},{{x}_{2}},...,{{x}_{m}})\,\!</math> ::<math>\underline{A}={{({{a}_{1}},{{a}_{2}},...{{a}_{m}})}^{T}}\,\!</math>
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  • {| style="text-align:center;" cellpadding="4" border="1" align="center" |1|| 2|| 1.95|| 3|| 6|| 6.04
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| F
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  • |All||1||Restores all accumulated damage.
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  • |style="width: 110px;"|Error||style="width: 70px;"|1||The diagnostic message pertains to an error.
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  • *The growth potential design margin factor is <math>GPDM=1.35\,\!</math>. ...he average fix delay in terms of test hours for each phase is: <math>{{L}_{1}}=10000\,\!</math>, <math>{{L}_{2}}=15000,\,\!</math> <math>{{L}_{3}}=20000
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  • The data set is from Table 15.1 on page 383 in the book ''Statistical Methods for Reliability Data'' by Dr. ...ey are defined by <math>\mu = ln(\eta)\,\!</math> and <math>\sigma = \frac{1}{\beta}\,\!</math>. The results are:
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  • ...erset{i}{\mathop \prod }}\,\frac{{{n}_{j}}-{{r}_{j}}}{{{n}_{j}}},\text{ }i=1,...,m\,\!</math> ...{s}_{j}}-\underset{j=0}{\overset{i-1}{\mathop \sum }}\,{{r}_{j,}}\text{ }i=1,...,m\,\!</math>
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  • {{template:RGA BOOK|4.1|Continuous Reliability Growth Planning}} ...={{\lambda }_{A}}+(1-d){{\lambda }_{B}}+d\lambda \beta {{t}^{\left( \beta -1 \right)}}\text{ for }t\ge {{t}_{0}}\,\!</math>
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  • ...or ''blocks'': runs that are carried out on the first day belong to block 1, and runs that are carried out on the second day belong to block 2. Thus, w ...could be as follows: one replicate of the experiment is assigned to block 1 and the second replicate is assigned to block 2 (now each block contains al
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  • |Inspection||1||Inspection task.
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  • ...mileage. The + indicates the latest mileage observed without failure. Car 1, for example, had a repair at 7068 miles and was observed until 26,744 mile {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
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  • Table 12.8 on page 419 in the book ''Reliability Engineering Handbook Vol 1'' by Dr. Kececioglu, Prentice-Hall, 1991. The least square estimator for <math>{\beta}\,\!</math> is 1.2 and for <math>{\eta}\,\!</math> is 146.2.
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  • | style="width: 100px;"|Weibull||style="width: 70px;"|1||Life data for use in Weibull++.
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  • | style="width: 150px;"|Define||style="width: 70px;"|1||Define at this level.
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  • ::*Failure Distribution: Weibull; <math>\beta = 1.5\,\!</math>; <math>\eta = 1,000\,\!</math> hours. ...d failure distribution: Weibull; <math>\beta =1.5\,\!</math>; <math>\eta = 1,000\,\!</math> hours.
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  • :*The scale parameter is <math>\tfrac{1}{\lambda }=\bar{T}-\gamma =m-\gamma \,\!</math>. :*The 1-parameter exponential reliability function starts at the value of 100% at <
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  • {{APIPrefix|Dim}} ModelParams(1) {{APIPrefix|As}} Double ModelParams(0) = 1
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  • ...ms, such as the 2-parameter form where <math>\gamma = 0,\,\!</math> or the 1-parameter form where <math>\beta = C = \,\!</math> constant, can easily be ...to reduce to those of other distributions. For example, when <math>\beta = 1\,\!</math>, the <i>pdf</i> of the 3-parameter Weibull distribution reduces
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  • |Generic||1||A generic action record.
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  • ...o a decreasing failure rate. The Weibull distribution having <math>\beta <1</math> is often used to depict this life characteristic. ...ential distribution and the Weibull distribution with <math>\beta \approx 1</math> .
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac In ALTA, the confidence bounds on time are the Type 1 bounds (Time Bounds).
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  • ::<math>f(t)=\frac{1}{\sigma }{{e}^{z-{{e}^{z}}}}\,\!</math> ::<math>F(t)=1-{{e}^{-{{e}^{z}}}}\,\!</math>
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  • ...for the MLE solution, likelihood ratio bound and Fisher Matrix bound for a 1-parameter exponential distribution with interval data in Weibull++ standard Example 7.1 on page 154 in the book ''Statistical Methods for Reliability Data'' by Dr.
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  • ...to a decreasing failure rate. The Weibull distribution having <math>\beta <1\,\!</math> is often used to depict this life characteristic. ...nential distribution and the Weibull distribution with <math>\beta \approx 1\,\!</math>.
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  • |Low||1||Low priority
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  • |Lognormal||1||Lognormal distribution.
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  • ::<math>L(V,U)=\frac{1}{V}{{e}^{A+\tfrac{B}{V}+CU+D\tfrac{U}{V}}}\,\!</math> ...{A+\tfrac{B}{{{V}_{U}}}+C{{U}_{U}}+D\tfrac{{{U}_{U}}}{{{V}_{U}}}}}}{\tfrac{1}{{{V}_{A}}}{{e}^{A+\tfrac{B}{{{V}_{A}}}+C{{U}_{A}}+D\tfrac{{{U}_{A}}}{{{V}_
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  • :1. Find the parameters for the data set, using the Rank Regression on X (RRX) :2. Obtain the probability plot for the data with 90%, two-sided Type 1 confidence bounds.
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  • | 10||1 | 100||1
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| 10|| 3
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  • {{template:ALTABOOK|10.1}} ::<math>L(x(t))={{e}^{{{\alpha }_{0}}+{{\alpha }_{1}}\ln \left( x(t) \right)}}\,\!</math>
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  • ...o follow a Weibull distribution. It is obtained by solving for <math>{{t}_{1}}\,\!</math> : :<math>R(t_1)=e^{(-\frac{t_1}{\eta})^\beta}= Uniform (0,1)\,\!</math>
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  • This page presents two alternative methods for comparing two data sets: 1) using contour plots and 2) using the Life Comparison tool in Weibull++.
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  • =Example 1= ==Published Results for Example 1==
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  • ::<math>ln(\eta)=\beta_{0}+\beta_{1} \times log(vpm) + \beta_{2} \frac{11605}{temp}\,\!</math> ...ath> &nbsp;, <math>\beta_{0} = 58.173\,\!</math>&nbsp;,&nbsp; <math>\beta_{1} = -12.28\,\!</math> &nbsp; and &nbsp; <math>\beta_{2} = 0.3878\,\!</math>
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  • [[Image:WB.23 lda26.1.png|center|250px| ]] \text{2}\text{.0187} & \text{1}\text{.9795} & \text{30}\text{.4216} & \text{33}\text{.6573} \\
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  • |ResetAfterAnalysis||1||Reset after each set of runs.
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  • |TypeI||1||Displays the bounds on time.
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  • ...!</math> and <math>D\,\!</math> are active at a significance level of 0.1. ...corresponds to a temperature of 333 <math>K\,\!</math> and the <math>+1\,\!</math> level corresponds to a temperature of 383 <math>K\,\!</math>.
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  • |Stress||1||A stress profile for use with the cumulative damage model in ALTA life-str
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  • The data are from Example 11-1 on page 71 in the book ''Design and Analysis of Experiments'' by Douglas C !style="background:#f0f0f0;"|1
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |1|| F
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  • |Mean||1||Mean value of the posterior distribution.
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  • | style="width: 150px;"|Reliability||style="width: 70px;"|1||Reliability model
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  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac '''Step 1:''' Insert an Equation Fit Solver folio in your project and enter the given
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  • {{template:RGA BOOK|3.1|Duane}} [[Image:rga4.1.png|center|450px|Cumulative MTBF vs. Cumulative Test Time postulated by Dua
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  • ...that belongs to MG 1 and Block 1 is set to be turned ON or OFF based on MG 1, this trigger is ignored. ...Block 3 would have to be directly associated with downing events of Block 1 for this to happen. The reason for this restriction is that allowing OFF ev
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  • |LikelihoodRatio||1||Likelihood ratio method.
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  • ...qrt{2\pi }}\int_{{{K}_{\alpha }}}^{\infty }{{e}^{-\tfrac{{{t}^{2}}}{2}}}dt=1-\Phi ({{K}_{\alpha }})\,\!</math> ...tfrac{1-\delta }{2}\,\!</math> for the two-sided bounds, and <math>\alpha =1-\delta \,\!</math> for the one-sided bounds.
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  • 1-CL=R^{n} ...is less than or equal to 80%, the chance of passing this test is 1-CL = 0.1, which is the Type II error. Therefore, the non-parametric binomial equatio
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  • ::<math>L(V)=\frac{1}{V}{{e}^{-\left( A-\tfrac{B}{V} \right)}}\,\!</math> [[Image:ALTA7.1.png|center|400px|Graphical look at the Eyring relationship (linear scale),
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  • ...h is the linear model <math>y = ax+ b\,\!</math> with parameters <math>a = 1\,\!</math> and <math>b = 0\,\!</math>). For the second phase, P2, the model ...h is the linear model <math>y = ax+ b\,\!</math> with parameters <math>a = 1\,\!</math> and <math>b = 0\,\!</math>). For the second phase, P2, the model
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  • ::<math>\Gamma ^{1} = \begin{bmatrix}
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  • ...qrt{2\pi }}\int_{{{K}_{\alpha }}}^{\infty }{{e}^{-\tfrac{{{t}^{2}}}{2}}}dt=1-\Phi ({{K}_{\alpha }})\,\!</math> ...\tfrac{1-\delta }{2}\,\!</math> for the two-sided bounds and <math>\alpha =1-\delta \,\!</math> for the one-sided bounds.
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  • ''100,000'' x ''$12.00'' = ''$1,200,000.00 <center><math>{{f}_{Market\_Share}}(R)=1-{{e}^{-{{\left( \frac{R}{a} \right)}^{b}}}}\,\!</math></center>
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  • |TwoSidedBoth||1||Two-sided confidence bounds.
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  • MyRepository.Project.SetCurrentProject(1)
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  • ...Weibull that is commonly referred to as such) offers an alternative to the 1-parameter Weibull, by including the variation and uncertainty that might ha ...square root of Fisher's information," yields <math> \varphi (\eta )=\dfrac{1}{\eta }\,\!</math>.
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  • 1. The log-time-to-failure for each unit follows a location-scale distributio \mu =\mu ({{z}_{1}})={{\gamma }_{0}}+{{\gamma }_{1}}x
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  • The restoration factor in BlockSim is defined as a number between 0 and 1 and has the following effect: ::#A restoration factor of 1 (100%) implies that the component is as good as new after repair, which in
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  • ...}\,\!</math> represent the time between failures ( <math>{{t}_{i}}=\sum_{j=1}^{i}{{x}_{j}})\,\!</math>. Assume that after each event, actions are taken v_{i}=v_{i-1}+qx_{i}=qt_{i}
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  • ...arply like an exponential ''pdf'' or a Weibull ''pdf'' with <math>0<\beta <1\,\!</math>.
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  • {{template:LDABOOK|10.1|The Lognormal Distribution}} ...>{{\Phi }^{-1}}\left[ F({t}') \right]=-\frac{{{\mu }'}}{{{\sigma}'}}+\frac{1}{{{\sigma }'}}\cdot {t}'\,\!</math>
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  • 1. Estimate the GRP model parameters using the Type I virtual age option. :1. The estimated parameters are <math>\hat{\beta }=1.1976\,\!</math>, <math>\hat{\lambda }=4.94E-03\,\!</math>, <math>\hat{q}=0.
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  • |Eyring||1||Eyring model.
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  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac {| | border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |F|| 25.3|| BD|| 3000|| || F|| 260.1|| BD|| 2000
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  • [[Image:406-1-2.png|center|800px|]]
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  • ...generalized gamma offers a compromise between the Weibull <math>(\lambda =1),\,\!</math> and the lognormal <math>(\lambda =0)\,\!</math> distributions. & {{\lambda }_{u}}= & 1.20736
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  • :Optional. Double. The duty cycle. Default value = 1.
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  • |Pending||1||The action is pending approval.
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  • ...For this, assume a constant rate for this occurrence with a probability of 1 every 50,000 miles. Assume a mission of 1,000 miles. If a tire fails during this trip, it will be replaced with the
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  • ::<math>P\left[ {{t}_{2}}\ge {{t}_{1}} \right]=\int_{0}^{\infty }{{f}_{1}}(t)\cdot {{R}_{2}}(t)\cdot dt\,\!</math> where <math>{{f}_{1}}(t)\,\!</math> is the ''pdf '' of the first distribution and <math>{{R}_{
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  • [[Image:rga7.1.png|center|450px]] The Gompertz model is mathematically given by Virene [[RGA_References|[1]]]:
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  • ...0%, average unit sale price is $2.10, average cost per unit to produce is $1.50 and other costs per failure is $0.50. The assumed maximum market potential is 1,000,000 units and the initial investment is $10,000.
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  • 1) Should the first failure at 406 K be included in the analysis? 1) Since the failure occurred at the very beginning of the test and for an un
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  • ...16, 32, etc. Therefore, the next design after the 2 <math>_{\text{III}}^{3-1}\,\!</math> design with 4 runs is the 2 <math>_{\text{III}}^{7-4}\,\!</math [[Image:doet8.1.png|center|487px|Highly fractional designs to investigate main effects.]]
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  • ::<math>R(t)={{R}_{1}}(t)\cdot {{R}_{2}}(t)\cdot ...\cdot {{R}_{n}}(t)\,\!</math> ...stribution can be either the 2-parameter Weibull, lognormal, normal or the 1-parameter exponential.
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  • [[Image:ALTAB.1.png|center|600px]] [[Image:ALTAB.1.1.png|center|600px]]
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  • The data is from Example 1-7 on page 46 in the book ''Reliability & Life Testing Handbook Vol 2'' by D
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  • {{template:LDABOOK|9.1|Normal Parameter Estimation}} ::<math>{{\Phi }^{-1}}\left[ F(t) \right]=-\frac{\mu}{\sigma}+\frac{1}{\sigma}t\,\!</math>
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  • |style="width: 170px;"|Incident||style="width: 70px;"|1||Imports incident data.
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  • ...ct of the <math>i\,\!</math>th level of factor <math>A\,\!</math> (<math>i=1,2,...,{{n}_{a}}\,\!</math>) ...ct of the <math>j\,\!</math>th level of factor <math>B\,\!</math> (<math>j=1,2,...,{{n}_{b}}\,\!</math>)
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  • === Method 1: Without subdiagram === *The reliability of all blocks follows a Weibull distribution with Beta = 1.5 and Eta = 500 hours.
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  • === Example 1 === *Both Block P and Block S have a Weibull distribution with Beta = 1.5 and Eta = 100 for reliability and repair action.
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  • |Scheduled||1||The spare part pool is restocked at fixed intervals.
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  • [[Image:ALTA10.1.png|400px|center|Life vs. Temperature (Arrhenius plot) at a fixed voltage l ...U}_{A}}}{{{U}_{u}}} \right)}^{n}}{{e}^{B\left( \tfrac{1}{{{V}_{u}}}-\tfrac{1}{{{V}_{A}}} \right)}}\,\!</math>
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  • NumberofElements = UBound(ListofEntities) - LBound(ListofEntities) + 1
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  • NumberofElements = UBound(ListofUnits) - LBound(ListofUnits) + 1
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  • ::<math>L(V)=\frac{1}{K{{V}^{n}}}\,\!</math> [[Image:ALTA8.1.png|center|400px|The inverse power law relationship on linear scales at dif
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  • ...een 0 and 100 indicates partial restoration. '''Double'''. Default value = 1. ...numeration, which specifies the effect of the restoration. Default value = 1 (restores all accumulated damage).
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  • {{APIPrefix|Call}} wds.AddFailure(100, 1) wds.AddFailure(100, 1)
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  • *The growth potential design margin factor is <math>GPDM=1.15\,\!</math>. ...conducted in seven phases. The cumulative phase end times are <math>{{T}_{1}}=4000,{{T}_{2}}=8000\,\!</math>, <math>{{T}_{3}}=12000,\,\!</math> <math>{
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  • NumberofElements = UBound(ListofProjects) - LBound(ListofProjects) + 1
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  • ::<math>ln(\eta) = \beta_{0} + \beta_{1} \times \frac{11605}{T}\,\!</math> ...These planning values were obtained based on the following assumptions: 0.1% of the units will fail in 6 months (183 hours) at 50°C, and 90% will fail
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  • ...die are the possible outcomes. Accordingly, the sample space is <math>S=\{1,2,3,4,5,6\}\,\!</math>. #The complement of <math>A\,\!</math> is: <math>\overline{A}=\{1,2,5\}\,\!</math>.
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  • ...e. In this case, the <math>\beta \,\!</math> of the fleet will be equal to 1 and the Crow Extended model can be used for quantifying the effects of futu {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
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  • ...qrt{2\pi }}\int_{{{K}_{\alpha }}}^{\infty }{{e}^{-\tfrac{{{t}^{2}}}{2}}}dt=1-\Phi ({{K}_{\alpha }})\,\!</math> ...\tfrac{1-\delta }{2}\,\!</math> for the two-sided bounds and <math>\alpha =1-\delta \,\!</math> for the one-sided bounds.
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  • ...s believed to be 70% effective, then the failure count can be reduced from 1 to 0.3 to reflect the effectiveness of the corrective action. {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
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  • :Optional. Double. The duty cycle. Default value = 1.
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  • ::<math>f(t)=\frac{1}{\sigma \sqrt{2\pi }}{e}^{-\frac{1}{2}(\frac{t-\mu}{\sigma})^2}\,\!</math> ::<math>\begin{align} R(t)= & 1-\int_{0}^{t}\lambda {{e}^{-\lambda s}}ds \\
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  • [[Image:ALTA9.1.png|center|400px|Life vs. Temperature plot at a fixed relative humidity.]] ...{V}_{u}}}-\tfrac{1}{{{V}_{A}}} \right)+b\left( \tfrac{1}{{{U}_{u}}}-\tfrac{1}{{{U}_{A}}} \right)}}\,\!</math>
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  • |Normal||1||Normal distribution.
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  • NumberofElements = UBound(ListofTaskTypes) - LBound(ListofTaskTypes) + 1
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  • |BlockFails||1||The task is performed when a block in the maintenance group fails.
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  • | style="width: 230px;"|Weibull1*||style="width: 70px;"|100||1-parameter Weibull |Exponential1*||106||1-parameter Exponential
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  • :Optional. Double. The duty cycle. Default value = 1.
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  • MyRepository.Project.SetCurrentProject(1)
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  • ...istribution of <math>T\,\!</math> is approximately chi-square with <math>n-1\,\!</math> degrees of freedom, where <math>n\,\!</math> is the number of te ::<math>T=2({{\hat{\Lambda }}_{1}}+...+{{\hat{\Lambda }}_{n}}-{{\hat{\Lambda }}_{0}})\,\!</math>
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  • |GlobalOnly||1||Return global resources only.
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  • 1. What is the unreliability of the units for a mission duration of 30 hours, 1. First, we use Weibull++ to obtain the parameters using RRX.
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  • ...tzmann's constant <math>(8.6173303\times {{10}^{-5}}\text{eV}{{\text{K}}^{-1}})\,\!</math>. [[Image:ALTA6.1.png|center|400px|Graphical look at the Arrhenius life-stress relationship (
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  • ::<math>\sum_{i=1}^{n}X_{i}=1\,\!</math> ...the term <math>P_{12}\,\!</math> is the transition probability from state 1 to state 2, and for any row <math>m\,\!</math> with <math>i\,\!</math> stat
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  • :Optional. Double. The duty cycle. Default value = 1.
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  • :<math>R(t) = (1 + \lambda t)e^{-\lambda t} \,\!</math> :<math>R(5000) = (1 + (3.6 \times 10^{-5}) \times 5000)e^{-(3.6 \times 10^{-5}) \times 5000} =
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  • ...set. '''String'''. If no name has been specified, the default name is "Set 1." ...ter is an integer that specifies the stress index, where 0 = first stress, 1 = second stress, etc. This property applies to the general log-linear (GLL)
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  • :Optional. Double. The duty cycle. Default value = 1.
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  • ...set. '''String'''. If no name has been specified, the default name is "Set 1." ...ter is an integer that specifies the stress index, where 0 = first stress, 1 = second stress, etc. This property applies to the general log-linear (GLL)
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  • #Determine the reliability of the component after 1 year (8,760 hours). #Rank the modes in order of importance at 1 year.
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  • :<math>y={{\beta }_{0}}+{{\beta }_{1}}{{x}_{1}}+\cdot \cdot \cdot +{{\beta }_{p}}{{x}_{p}}+\varepsilon \,\!</math> • <math>{{x}_{1}}\,\!</math>, …, <math>{{x}_{p}}\,\!</math> are the factors
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  • :Optional. Double. The duty cycle. Default value = 1.
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  • {{Template:Doebook|8.1}} ...umn for <math>ABC\,\!</math> has entries of 1). The resulting <math>{2}^{3-1}\,\!</math> design has a design matrix as shown in figure (b) below.
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  • {|width="350" border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac |System #|| 1|| 2|| 3|| 4|| 5|| 6
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  • ...ake on one of only two values (let's say defective = 0 and non-defective = 1). In this case, the variable is said to be a discrete random variable. ...of <math>x\,\!</math>. The total area under the ''pdf'' is always equal to 1, or mathematically:
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  • |Node||1||Node block
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  • ::<math>\text{Time-to-Failure}_{i}=t_{i}-r_{i-1}\,\!</math> :::* <math>i=1,...n\,\!</math>
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  • |ItemAge||style="width:70px"|1||Fixed time frame based on item's age.
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  • |Reliability||1||Reliability vs. time plot.
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  • ...duct a specific task a fixed number times for each hour of operation (task 1). ...can mask a major reliability problem. In other cases during testing, tasks 1, 2 and 3 might never meet their stated averages, except perhaps at the end
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  • |SubSev(1-8)Init||Gets or sets the initial sub-severity rating. There are a total of |SubSev(1-8)Rev||Gets or sets the revised sub-severity rating. There are a total of e
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  • [[Image:doet6.1.png|center|410px|Surface finish values for three speeds of a lathe machine. ...icates at each level then <math>i=1,2,...,{{n}_{a}}\,\!</math> and <math>j=1,2,...,m\,\!</math>. The random error terms, <math>{{\epsilon }_{ij}}\,\!</m
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  • \end{matrix} \right){{Z}^{k}}{{\left( 1-Z \right)}^{N-k}}\,\!</math> \end{matrix} \right){{Z}^{k}}{{\left( 1-Z \right)}^{N-k}}\,\!</math>
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  • {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
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  • This example validates the results for a Rayleigh distribution (1-parameter Weibull with beta = 2) in Weibull++ standard folios.
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  • ===Example 1: Reliability Data===
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  • {|border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac !System 1
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  • MyRepository.Project.SetCurrentProject(1)
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  • MyRepository.Project.SetCurrentProject(1)
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  • ...ributions. Note that although all forms are mentioned below, ALTA uses the 1-parameter form of the exponential distribution and the 2-parameter form of
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  • ...ies whether the data set is for use with Weibull++ or RGA. Default value = 1 (use with Weibull++).
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  • ...number of failures are found after Y hours of test time. Failures <math>X_{1}\,\!</math>, <math>X_{2}\,\!</math>, <math>X_{3}\,\!</math>, etc. could hav ...s, and corrective action is again implemented on both units; however, unit 1 has accumulated 5 hours of operating time and unit 2 has accumulated 7 hour
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  • MyRepository.Project.SetCurrentProject(1)
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  • \text{1} & \text{105} & \text{106} \\
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  • MyRepository.Project.SetCurrentProject(1)
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  • ===Example 1===
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  • MyRepository.Project.SetCurrentProject(1)
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  • The data set is from Table 2.1 on page 496 in the book ''Accelerated Testing: Statistical Models, Test Pla ...age (Kilovolts) and the insulation thickness given on page 495 and Table 2.1. For all the stress profiles, the holding time for the first 4 steps is 10
    13 KB (1,821 words) - 18:22, 28 September 2015
  • MyRepository.Project.SetCurrentProject(1){{APIComment|'Replace with the object ID of test project.}}
    1 KB (142 words) - 18:16, 3 April 2017
  • ...lation or be reset to its initial value at specific times. Default value = 1 (reset after each set of runs).
    1 KB (178 words) - 17:46, 12 March 2019
  • ::<math>ln(\eta) = \beta_{0} + \beta_{1} \times \frac{11605}{T}\,\!</math> ...These planning values were obtained based on the following assumptions: 0.1% of the units will fail in 6 months (183 hours) at 50°C, and 90% will fail
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  • MyRepository.Project.SetCurrentProject(1){{APIComment|'Replace with the object ID of test project.}} ...pository1.rsr11" exists in the C drive and that we're accessing project ID#1. If you're copying this section of code, be sure to replace the inputs with
    6 KB (800 words) - 18:15, 3 April 2017
  • {{template:LDABOOK|8.1|Weibull Parameter Estimation}} {| border="1" align="center" style="border-collapse: collapse;" cellpadding="5" cellspac
    23 KB (3,505 words) - 16:31, 3 July 2023
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